If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5n^2-26n-24=0
a = 5; b = -26; c = -24;
Δ = b2-4ac
Δ = -262-4·5·(-24)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*5}=\frac{-8}{10} =-4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*5}=\frac{60}{10} =6 $
| -7(-2x=7)=105 | | 8f+14=12f | | 90-x=47 | | 8x+15=2x+3 | | 6m+2=2(4m+1) | | 6(x+1)=7(2x=10) | | 11b-4b=7 | | 15-4=x | | y^2-3y+2=72 | | 9x+14=5x+27 | | x=18x+4 | | (2p+1)+(3-4)+(3-1p)=3p+1 | | 5(2x+1)=18x | | x+x=x4 | | 25+x=-3x+3(1+6x) | | t-7=3+2t | | 3x-5=21x-1 | | 13+x=143 | | u/7.5=10/7.5 | | 9j-6j=6 | | -8(x+2)-5x=2X+14 | | x+x=10+10 | | 3/4g-5=10 | | k+1/6=15/12 | | x-87-43-(-75)=x | | 8(x+2)-5x=2X+14 | | (2x+3)^(2)=36 | | 13+z=60 | | 8+3/5(2n-15)=23 | | 3v^2+4=4-2v | | -5x-8=6x-41 | | 8+8=-4(4x-4) |